[apparmor] [PATCH 8/8] utils: Set parser executable path according to USE_SYSTEM make variable

[Seth Arnold]

On Wed, Feb 08, 2017 at 10:01:45PM +0000, Tyler Hicks wrote:
> if USE_SYSTEM is not set, the utils make check target will instruct
> test-aa-easyprof.py to provide the path of the in-tree parser executable
> to aa-easyprof.
> 
> If USE_SYSTEM is set, the default parser path (/sbin/apparmor_parser or
> the result of `which apparmor_parser`) is used.
> 
> The test-aa-easyprof.py script receives the parser path by checking the
> __AA_PARSER environment variable. This environment variable is strictly
> used by the test script and not any user-facing code so two leading
> underscores were used.
> 
> Signed-off-by: Tyler Hicks <tyhicks at canonical.com>
> Cc: Christian Boltz <apparmor at cboltz.de>
> Cc: Jamie Strandboge <jamie at ubuntu.com>
> ---

This appears to suffer a similar problem:

> +        # Check __AA_PARSER, which may be set by the Makefile, to see if
> +        # we should use a non-default apparmor_parser path to verify
> +        # policy
> +        parser = os.getenv('__AA_PARSER')
> +        if parser:
> +            self.full_args.append('--parser=%s' % parser)
> +
>          if debugging:
>              self.full_args.append('-d')

Thanks
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