win32 file locking

[Aaron Bentley]

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John A Meinel wrote:
> The problem is that Branch() is commonly used as a temporary object. For
> instance the 'bzr revno' command is done like:
> 
> print Branch('.').revno()
> 
> How do you unlock a branch if you never have an object to call
> 'unlock()' on?

I guess one option would be to provide convenience functions like this:

def branch_revno(path='.'):
    b = Branch(path, lock_mode='r')
    revno = b.revno()
    b.unlock()
    return b

i.e. eliminate all use of Branch temporaries by making it really easy to
do it the Right Way.

Aaron
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