[Bug 1446291] Re: gcc/g++ 4.8.2 won't convert uint64 to char properly.

[Роман Донченко]

I don't think that's a bug. char is unsigned on ARM by default. Use
signed char instead.

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Title:
  gcc/g++ 4.8.2 won't convert uint64 to char properly.

Status in gcc-4.8 package in Ubuntu:
  New

Bug description:
  I have an Ubuntu 14.04 system for arm7l (armhf), and I think
  I have found a bug in the g++/gcc compiler.

  I am expecting to see 'char c' below to end up as a negative number,
  but as you can see, it does not.  x86 system shows the negative number
  as expected.

  Anyone have any ideas for a work-around, or proper code if mine is
  buggy?


  greearb at build-imx6:~/git/btbits/server$ more test.cc
  #include <stdlib.h>
  #include <stdio.h>

  int main() {
     unsigned long long val = 0x8b;
     char c = val;
     printf("c: %d  0x%x\n", c, c);
     return 0;
  }
  greearb at build-imx6:~/git/btbits/server$ g++ -o test test.cc
  greearb at build-imx6:~/git/btbits/server$ ./test
  c: 139  0x8b
  greearb at build-imx6:~/git/btbits/server$

  greearb at build-imx6:~/git/btbits/server$ g++ --version
  g++ (Ubuntu/Linaro 4.8.2-19ubuntu1) 4.8.2
  Copyright (C) 2013 Free Software Foundation, Inc.
  This is free software; see the source for copying conditions.  There is NO
  warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.


  On x86 system:

  [greearb at ben-dt ~]$ g++ -o test test.cc
  [greearb at ben-dt ~]$ ./test
  c: -117  0xffffff8b

  [greearb at ben-dt ~]$ gcc --version
  gcc (GCC) 4.7.2 20121109 (Red Hat 4.7.2-8)

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