[Bug 1665752] Re: Cannot make simple connection with new python3-crypto version
Hans Joachim Desserud
1665752 at bugs.launchpad.net
Fri Feb 17 22:23:46 UTC 2017
*** This bug is a duplicate of bug 1665565 ***
https://bugs.launchpad.net/bugs/1665565
Thank you for taking the time to report this bug and helping to make
Ubuntu better.
This has already been reported as bug 1665565, so I'm taking the liberty
of marking this as a duplicate. Note that python-crypto
2.6.1-6ubuntu0.16.04.2 has been released for 16.04 which backs down from
throwing an exception to printing a warning, see bug 1665598 for more
details.
** Tags added: regression-update xenial
** This bug has been marked a duplicate of bug 1665565
python-paramiko 1.16.0-1 incompatible with python-crypto 2.6.1-6ubuntu0.16.04.1
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https://bugs.launchpad.net/bugs/1665752
Title:
Cannot make simple connection with new python3-crypto version
Status in paramiko package in Ubuntu:
New
Bug description:
The automatic updates applied a new version of python3-crypto which
now breaks paramiko ssh connections.
The change log for crypto shows me this, which is exactly the error I am seeing.
python-crypto (2.6.1-6ubuntu0.16.04.1) xenial-security; urgency=medium
* SECURITY UPDATE: throw exception when IV used with ECB or CTR
- debian/patches/CVE-2013-7459.patch: force exception when IV used ECB/CTR
- CVE-2013-7459.patch
-- Emily Ratliff <emily.ratliff at canonical.com> Tue, 14 Feb 2017
16:05:02 -0600
I found the upgrade from /var/log/apt/history.log
Start-Date: 2017-02-17 07:04:27
Commandline: /usr/bin/unattended-upgrade
Upgrade: <clipped> python3-crypto:amd64 (2.6.1-6build1, 2.6.1-6ubuntu0.16.04.1), <clipped>
End-Date: 2017-02-17 07:04:56
$ lsb_release -rd
Description: Ubuntu 16.04.1 LTS
Release: 16.04
$ apt-cache policy python3-paramiko
python3-paramiko:
Installed: 1.16.0-1
Candidate: 1.16.0-1
Version table:
*** 1.16.0-1 500
500 http://us.archive.ubuntu.com/ubuntu xenial/main amd64 Packages
500 http://us.archive.ubuntu.com/ubuntu xenial/main i386 Packages
100 /var/lib/dpkg/status
$ apt-cache policy python3-crypto
python3-crypto:
Installed: 2.6.1-6ubuntu0.16.04.1
Candidate: 2.6.1-6ubuntu0.16.04.1
Version table:
*** 2.6.1-6ubuntu0.16.04.1 500
500 http://us.archive.ubuntu.com/ubuntu xenial-updates/main amd64 Packages
500 http://security.ubuntu.com/ubuntu xenial-security/main amd64 Packages
100 /var/lib/dpkg/status
2.6.1-6build1 500
500 http://us.archive.ubuntu.com/ubuntu xenial/main amd64 Packages
A simple test that should connect (and used to) but now doesn't
Python 3.5.2 (default, Nov 17 2016, 17:05:23)
[GCC 5.4.0 20160609] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import paramiko
>>> ssh = paramiko.SSHClient()
>>> ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
>>> ssh.connect("192.168.2.46", username='xxxx', password='xxxx')
Unknown exception: CTR mode needs counter parameter, not IV
Traceback (most recent call last):
File "/usr/lib/python3/dist-packages/paramiko/transport.py", line 1744, in run
self.kex_engine.parse_next(ptype, m)
File "/usr/lib/python3/dist-packages/paramiko/kex_group1.py", line 75, in parse_next
return self._parse_kexdh_reply(m)
File "/usr/lib/python3/dist-packages/paramiko/kex_group1.py", line 112, in _parse_kexdh_reply
self.transport._activate_outbound()
File "/usr/lib/python3/dist-packages/paramiko/transport.py", line 2074, in _activate_outbound
engine = self._get_cipher(self.local_cipher, key_out, IV_out)
File "/usr/lib/python3/dist-packages/paramiko/transport.py", line 1649, in _get_cipher
return self._cipher_info[name]['class'].new(key, self._cipher_info[name]['mode'], iv, counter)
File "/usr/lib/python3/dist-packages/Crypto/Cipher/AES.py", line 94, in new
return AESCipher(key, *args, **kwargs)
File "/usr/lib/python3/dist-packages/Crypto/Cipher/AES.py", line 59, in __init__
blockalgo.BlockAlgo.__init__(self, _AES, key, *args, **kwargs)
File "/usr/lib/python3/dist-packages/Crypto/Cipher/blockalgo.py", line 141, in __init__
self._cipher = factory.new(key, *args, **kwargs)
ValueError: CTR mode needs counter parameter, not IV
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