moving file using perl
Chris G
cl at isbd.net
Thu May 1 09:02:30 UTC 2008
On Thu, May 01, 2008 at 11:27:58AM +0300, OOzy Pal wrote:
> On Thu, May 1, 2008 at 10:54 AM, Chris G <cl at isbd.net> wrote:
> > On Thu, May 01, 2008 at 10:41:21AM +0300, OOzy Pal wrote:
> > > Hello,
> > >
> > > How can I move a file to a directory name DONE using perl. I tried
> > > this but it did not work?
> > >
> > > $file='Myfile';
> > > rename $file, 'Done/'$file;
> > >
> > ... and what error message did you get? Does the directory exist (and
> > remember 'DONE' and 'Done' are different in Linux/Unix)?
> >
>
> Here is the error
> Scalar found where operator expected at /home/hab/bin/exiftool.pl line
> 45, near "'DONE/'$file"
> (Missing operator before $file?)
> syntax error at /home/hab/bin/exiftool.pl line 45, near "'DONE/'$file"
> Execution of /home/hab/bin/exiftool.pl aborted due to compilation errors.
>
My perl is a bit rusty (I've settled on Python as my language of
choice, much 'cleaner' IMHO) but the error is simple - you can't just
put 'Done/'$file and expect perl to concatenate the two. You have to
use the string concatenation operator, e.g.:-
rename $file, 'Done/' . $file;
--
Chris Green
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